What is produced at each electrode in the electrolysis of NaBr?

What is produced at each electrode in the electrolysis of NaBr?

Na(s)

Br2(l)

O2(g)

p(g)

Which ones are anodes, cathodes, or not produced?

Answer:

Sophie,

The anode is where oxidation takes place, the cathode is where reduction takes place.

In the electrolysis of NaBr,

the oxidation is 2Br^- —> Br2(l) + 2e^-; E = -1.066 volts (that’s the anode)

the reduction is 2H2O + 2^e− —> p(g) + 2OH−; -0.8277 volts (that’s the cathode)

Sodium metal would not form it water, as it would immediately re-oxidize. Also, if the voltage is controlled, oxygen will not form at the anode.

Hope that helped!

Shortening what ^ Dr. Buzz said:

Br2(l) forms at the anode, p(g) forms at the cathode, and Na(s) and O2(g) are not produced.

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