The Best Answer for what is the enthalpy for the following reaction? C2H4 + H20 –> C2H5OH?
C2H4 + H20 –> C2H5O
formation enthalpy of ethane -> –83.8 kJ/mol
formation enthalpy of water -> −291.83 kJ/mol
formation enthalpy of ethanol -> –277.7 kJ/mol
Since the equation is properly balanced, then the enthalpy change is just
-277 + 291 + 83 = 97
So, the enthalpy of the reaction is just 97 kJ/mol