# [SOLVED] Tempestt graphs a function that has a maximum located at (–4, 2).

Tempestt graphs a function that has a maximum located at (–4, 2).

Tempestt graphs a function that has a maximum located at (–4, 2). Which could be her graph? On a coordinate plane, a parabola opens up. It goes through (negative 6, 6), has a vertex at (negative 4, 2), and goes through (negative 2, 6). On a coordinate plane, a parabola opens up. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6). On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 2), has a vertex at (negative 4, 2), and goes through (negative 2, negative 2). On a coordinate plane, a parabola opens down. It goes through (2, negative 2), has a vertex at (4, 2), and goes through (6, negative 2)

The correct answer for Tempestt graphs a function that has a maximum located at (–4, 2).

Given : Tempestt graphs a function that has a maximum located at (–4, 2)

To find : Which could be her graph

Solution:

Tempestt graphs a function that has a maximum located at (–4, 2)

=> for  x  = – 4   , the  y = 2  is the maximum value

hence ( – 4 , 2) is the vertex

hence every point on graph would be less than 2  on y – axis  for any x

It goes through (- 6, 6), has a vertex at (- 4, 2), and goes through -2, 6).

not possible as y = 6 > 2

. It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6).

not possible as y = 6 >  2

it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).

vertex (-4 , 2)

y < 2

This Could be her Graph

It goes through (2, -2), has a vertex at (4, 2), and goes through (6, -2).

not possible as vertex here is (4 , 2)  instead of (-4,2)

Her Graph

On a coordinate plane, a parabola opens down it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).