A 18-cm-radius air duct is used to replenish the air of a room 10.2 m x 5.0 m x 5.5 m every 18 minutes. How fast does air flow in the duct?

Answer:

This is the Best answer to this question.

The volume of the room is:

V = (10.2m)(5.0m)(5.5m) = 280.5m^3

The amount of air flowing through the duct each minute is:

280.5m^3/18m = 15.5833m^3/min

The area of the duct times the velocity of airflow must equal 15.5833m^3/min.

Area = Pi(r^2) = Pi(0.18m)^2 = 0.1018m^2

Velocity x 0.1018m^2 = 15.5833m^3/min.

Velocity = (15.5833m^3/min) / (0.1018m^2)

Velocity = 153.0962m/min, or

Velocity = (153.0962m/min)/ 60s/min = 2.5516m/s

This is the correct answer for A 18-cm-radius air duct is used to replenish the air of a room 10.2 m x 5.0 m x 5.5 m every 18 minutes. How fast does air flow in the duct?