Find the electric field at the origin, point O. Give the x and y components of the electric field as an ordere?
PART 1:
Two point charges are placed on the x axis. (Intro 1 figure) The first charge, = 8.00 , is placed a distance 16.0 from the origin along the positive x axis; the second charge, = 6.00 , is placed a distance 9.00 from the origin along the negative x axis.
PART 2:
Now, assume that charge q2 is negative; q2 = -6nC. (Part B figure) What is the net electric field at the origin, point O?
Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.
Answer:
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Let a positive field be to the right so q1 will generate a + field and q2 a negative field
So E = k*(q1/r1^2 – q2/r2^2) = 9.0×10^9*(6.0×10^-9/9^2 – 8×10^-9/16^2) = 0.385 N/C
Part 2 Now both field point to the left so
E = k*(-q1/r1^2 – q2/r2^2) = 9.0×10^9*(-6.0×10^-9/9^2 – 8×10^-9/16^2) = -0.948 N/C
How could i’m getting ? if the two rather one in all my expenditures are 4 micro C placed at x= 1m and x =-1m and that i could prefer to calc the value E of the internet electric powered field at y= 0.6m? idk what to anticipate x and y to plug into arctan?, the only way i think of like i visit do it finally finally end up being 0 by employing actuality it may properly be arctan(0/0.6)
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