[SOLVED] Dry air will break down if the electric field exceeds 3×10^6 V/m…?

Dry air will break down if the electric field exceeds 3×10^6 V/m…?

Dry air will break down if the electric field exceeds 3×10^6 V/m. What amount of charge can be placed on a capacitor if the area of each plate is 68 cm2?

Answer:

This is the best answer for Dry air will break down if the electric field exceeds 3×10^6 V/m…?

The capacitance can be calculated:

C = ε*A/d

Where “ε” is the permittivity of free-space, “A” is the plate area, and “d” is the distance separating the plates.

The maximum voltage can be calculated:

Vmax = 3*10^6*d

Q = C*V

Q = (ε*A/d)*3*10^6*d

The “d” cancels:

Q = ε*A*3*10^6 = 8.854*10^-12*( 68/10^4 )*3*10^6 = 181*10^-9 C

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