Answer:
This is the Best answer for Calculate the molar solubility of lead thiocyanate in 0.600M KSCN?
Pb(SCN)2 <==> Pb^2+ + 2 (SCN)^-
. . s . . . . . . . . . .. . s . . . . . . 2s
KSCN ————-> K+ + SCN-
0.600 . . . . . . . . . . . . . . . 0.600
Ksp = [Pb^2+][CN^-]^2
2.00 10^-5 = (s)(2s+0.600)^2
s = 5.55 10^-5
the molar solubility of lead thiocyanate in 0.600M KSCN = 5.55 10^-5 mol/L