Calculate H+ : a solution in which [OH -] is 140 times greater than [H+]?

The Best answer for Calculate H+ : a solution in which [OH -] is 140 times greater than [H+]?

Let x = [H+]. Then, [OH-] = 140 x. You know that [H+] X [OH-] = 1 X 10^-14.

So,

(x) (140x) = 1 X 10^-14

140 x^2 = 1 X 10^-14

x^2 = 7.14 X 10^-17

x = 8.45 X 10^-9 M = [H+]