This is the Best answer for Calculate H+ : a solution in which [OH -] is 100 times greater than [H+]?
In a neutral solution;
[H+] = [OH-] = 1×10^-7 M
Since [OH-] greater than [H+], the solution is basic.
In all solutions, whether neutral, or acidic or basic,
Kwater should be satisfied.
Kw = [H+][OH-] = 1×10^-14
Since [OH-] = 100[H+]
Kw = [H+] x 100 [H+] = 1×10^-14
[H+]^2 = 1×10^-14 / 100 = 1×10^-16
[H+] = 1×10^-8 M
[OH-] = Kw / [H+] = 1×10^-14 / 1×10^-8 = 1×10^-6 which is 100 times greater than 1×10^-8
Let’s assume the solution is Water which is:
HOH, and at equilibrium it is exactly balanced:
H+ + OH-
Now, you are saying that OH is increased by 100% or:
2 X 10 ^ 2
This would make H+ 100 times LESS than OH – or
2 X 10^-2
Therefore, H+ has a value of 2 X 10 ^-2 less in concentration in comparison to OH –
This is the correct answer for Calculate H+ : a solution in which [OH -] is 100 times greater than [H+]?