Answer:

…

1/f = 1/o = 1/di

find di of 1st lens

1/5 = 1/4 + 1/di

di = -20 cm (to left of 1st lens)

this plus distance between lenses is now the do for 2nd lens

20 + 12 = 32

then

1/-8 = 1/32 + 1/di

di = -6.4 cm

so final image is 6.4 cm LEFT of the 2nd lens [[1st answer]]

find magnification of both lenses

M = – do/di

M1 = – (-20 / 4) = +5

M2 = – (-6.4 / 32) = +0.2

overall M is this product

M = M1 * M2 = 5 * .0.2 = 1

so the final image is the same size as the 1st object

summary

we have an upright image, 1.0 cm tall at 6.4 cm left of the 2nd lens

When you get a good response,

please consider giving a best answer.

This is the only reward we get.

You may have to wait an hour to award BA.